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Boomer · 11/06/2009, 03:56 PM

Blue

Look at the periodic chart here

Now look for Na, O and H Molecular weight

Na = 22.99 grams = 1 mol

O = 16 grams = 1 mol

H = 1.08 grams = 1mol

NaOH has 1 Na, 1 O and 1 H

So, 1 mol of each = 1 mol of NaOH

So, 22.9 + 16 + 1.08 = 38.98 grams = 1 mol of NaOH or ~40 grams = 40,000 ppm

0.1 mol would equal = 4 grams= 4,000 ppm. 1 mmol = 0.04 grams = 40 ppm

If it was 1 mol of CaCO3, has 1 Ca, 1 C and 3 O

~ 40 + ~12 + (3 x 16) = 100 grams = 1000,000 ppm of CaCO3 = 1 mol

mmol times Molecular weight = ppm

and

ppm / Molecular weight = mmol

NSW has 10.27 mmol (0.01027 mol) of Ca++. So, 10.27 x 40 = 411 ppm or 411 ppm x 1.023 d = 420 mg/ l Ca++ .
NSW has 411 ppm / 40 molecular weight of Ca = 10.27 mmol

You do not use things like mg/ l or ppm for solving equations in chem but mol or mmol

11/06/2009, 03:56 PM	#16
Boomer Bomb Technician (EOD) Join Date: Aug 2002 Location: Duluth, Minnesota Posts: 11,842	Blue Look at the periodic chart here Now look for Na, O and H Molecular weight Na = 22.99 grams = 1 mol O = 16 grams = 1 mol H = 1.08 grams = 1mol NaOH has 1 Na, 1 O and 1 H So, 1 mol of each = 1 mol of NaOH So, 22.9 + 16 + 1.08 = 38.98 grams = 1 mol of NaOH or ~40 grams = 40,000 ppm 0.1 mol would equal = 4 grams= 4,000 ppm. 1 mmol = 0.04 grams = 40 ppm If it was 1 mol of CaCO3, has 1 Ca, 1 C and 3 O ~ 40 + ~12 + (3 x 16) = 100 grams = 1000,000 ppm of CaCO3 = 1 mol mmol times Molecular weight = ppm and ppm / Molecular weight = mmol NSW has 10.27 mmol (0.01027 mol) of Ca++. So, 10.27 x 40 = 411 ppm or 411 ppm x 1.023 d = 420 mg/ l Ca++ . NSW has 411 ppm / 40 molecular weight of Ca = 10.27 mmol You do not use things like mg/ l or ppm for solving equations in chem but mol or mmol __________________ If you See Me Running You Better Catch-Up Seawater Chemistry, Geology, ID Marine Life, Collecting Science Books, Explosives Technology, Audiophile An explosion can be defined as a loud noise, accompanied by the sudden going away of things, from a place where they use to be.