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10/16/2018, 07:50 PM | #1 |
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calling all Alluminum heatsink expert
hi all I need some input /help
I was given 2 pieces of Aluminum plates their measure is L 48" x W 4 1/4 x 1/4 thick and around 4-5 pounds in weight the question is.... can I use this as heat sink for a DIY Led Project? thanks. [IMG]Aluminum plates [IMG]Aluminum plates [IMG]Aluminum plates
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10/17/2018, 02:10 AM | #2 |
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Short answer? Yes, maybe, and no.
Longer answer is it depends. How much heat you are pumping into it, for how long, in what sort of conditions, etc... It won't be good at getting rid of heat (relatively speaking low surface area, and its thick) but it will soak some up for a while. That while could be enough, or it could be lots too little... How much heat are you planning on making? |
10/17/2018, 04:44 AM | #3 |
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^ yep..
Of course it can be a heatsink... Most black box LEDs just use an aluminum plate that has no fins at all.. If its sufficient or not for your build depends on the specifics of your build.. It will easily handle all of those LEDs in the back of picture 1... Being a "good" heatsink is about surface area.. A flat plate by itself doesn't have nearly the surface area of one with tons of fins/pins or whatever...
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10/17/2018, 05:46 AM | #4 |
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Hi guys thanks for the reply
I'm planning to put 12 leds of 10 watts each ,on each plate Thanks again
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10/17/2018, 06:12 PM | #5 | |
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no expert and thermal management is sort of part art,science, and trial ..BUT this is a bit of a "rule of thumb" approach..
Quote:
you have approx 408 sq inches...thickness is really of lesser importance and adds little, at about "2W" of heat dissipation w/ the conservative approach.. So one "rule" says you can do like 430W another one says 35W... Pick one or in-between... Now that also assumes you are actually going to RUN them at 10W which, if cheap chips, wouldn't be recommended anyways.. |
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10/17/2018, 08:03 PM | #6 |
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Wow didn't know
All these rules And yes they are two Opposite data's 12 sqi x watt ?? Wondering what the Companies are using For the black box
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10/17/2018, 08:08 PM | #7 |
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Thanks Oreo
Definitely sucks though I have drivers that have to run 12 at the time
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10/18/2018, 10:17 AM | #8 |
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12in^2 per watt? ha ha ha ha...
Black box LEDs are doing WAY more wattage than that...
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10/18/2018, 11:33 AM | #9 | |
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Quote:
Can you clarify please. As I'm not understanding... Thanks
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10/18/2018, 01:10 PM | #10 | |
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Quote:
first off I want to say 12 sq inches per watt IS extreme but ssumes passive cooling.. BB's use 2 fans....and run about 2W at the diodes.. 100W-ish is probably a more realistic "guess".. 180 sq " boards..Lets just say 2 sq " per watt w/ active cooling.. Reefbreeders use finned heatsinks and fans on some of their boxes.. Actually surface area "could be" is much larger.. based on this: It's a Mars Aqua hort light. much bigger than a black box though. CORRECTIONS: suspect smaller bb's have no finned heat sink Many use 3 fans for cooling.. @12square inches per real watt. for 100w flat plate would be around 34"x17" plate passive.. w a large margin of error (not really subtracting any diode footprints.) Last edited by oreo57; 10/18/2018 at 01:45 PM. |
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10/18/2018, 02:00 PM | #11 |
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So if I install 24 leds of 10 watts each, and run them at 900 MA
or 850 ma instead of 1000 and also installing 3 fan on the top should be ok? Not the best but ok? Thanks
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10/18/2018, 09:34 PM | #12 |
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Personally, I dislike fans but a lot depends on where you put the lights.. You encoded? Open top ect..
I really don't think you will have an issue w/out the fans and lower currents...900-ish might push each to it's 10W depends on the chip.. to be honest, it's going to be a bit of trial and error.. What drivers are you planning on using? |
10/21/2018, 06:35 AM | #13 |
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Hi there I have 2 meanwell
Hlg 120 H I have using one for 3 year now
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10/21/2018, 09:56 AM | #14 |
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There are dozen of models of HLG120's..
anyways I guess you are planning on running the 10W chips in parallel to divide the driver output current.. Since most common 10W chips run around 34V V(f) and 120 drivers capable of that voltage have 4A or less available.. Soo @ 6 per driver your max current to each is 600mA to 300mA |
10/21/2018, 12:23 PM | #15 |
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Hi there the leds are in Serial,
The driver puts out 120V at 1a Right now on my old rail I'm running 11 leds The leds can be run at 10 to 12 volts 120 /11 = 10.9 volts @1000 mA
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10/25/2018, 08:33 PM | #16 |
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I suggest you run some tests if you already have the LEDs and drivers. Take some readings and see where the temp starts to level out. Surface area is the key but a small fan can make a big difference.
Typically, LED intensity starts to diminish above 105 deg f and if you run them long over 135, they won't last. I've been using these 3.5 inch pucks that you can find on eBay. They have less than 10 sq in on each but there are (15) one watt LEDs on them, so.. far greater than the amount recommended above. There are no fins but i do have a small fan blowing on four of them. Without the fan they would burn up in a day or two. I put a temp probe on one of them and monitor it with the Apex. These are my refugium lights. If the temp goes above 110, I shut them off. I've attached the temp graph. |
10/25/2018, 09:13 PM | #17 |
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I can't see that alloy plate being useful much at all. The life of the LEDs will be diminished greatly if they are not cooled efficiently.
Basically, an LED produces a lot of heat behind the chip & this heat needs to be sucked, or absorbed away from the chip to keep the chip at a reasonable operating temperature. A heatsink absorbs this heat. But the heatsink must be able to cool quickly & efficiently itself so it doesn't over heat. If it can't cool rapidly enough its temperature gets closer to the temperature produced at the chip & its ability to absorb enough heat away from the chip is drastically diminished. So the heatsink cannot be made from a material (normally aluminum) that is too thick because it will hold the heat. As already pointed out fins greatly increase the surface area of a heatsink and that enables it to radiate heat - loose heat, much more quickly/efficiently. This is a heatsink I use. The base is only 2mm thick, & the fins 1mm thick. |
10/25/2018, 09:28 PM | #18 |
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Thanks ozla
I need to check the temp I think tha is above the 100 f Thanks for the suggestion Twinfallz Did you buy that heatsink locally?
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10/25/2018, 09:37 PM | #19 |
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10/26/2018, 11:24 PM | #20 | ||
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Quote:
This is enough to passive cool 10W chips (at least for me for a few years b4 abandoning the build). Granted a lot of surface area and a lot of convection air movement arounfd the sink but not really very big. Temps would easily go over 120F.. SECOND there is a large difference between cheap chips and quality modern chips: Quote:
NOTE: That is at the core not the sink. Easiest "fix" if you think the chips are heating too much is just tweak the drive current down a bit.. Less current less heat but oddly the LED's become more efficient.. Oh and yes black anodizing.. and even black paint radiates heat off the sink better than a raw or polished surface. Not needed for fan cooled though. I've seen plenty of things that shouldn't work, work just fine.. Would it be my choice? No. But it's free, large and, if needed, can be enhanced w/ thermal pasting some fins on top.. Cheap 10W chips are like $2.50 each... Again, heat sinking is complicated and even manf need to do Real world tests over any calcs and guessing.. Last edited by oreo57; 10/26/2018 at 11:39 PM. |
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10/27/2018, 01:50 AM | #21 |
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The color of a heatsink plays no part in its ability to radiate heat (loose heat - cool down). A coating of paint will act as an insulation & restrict heat loss in fact. A black surface absorbs light energy better than another colored surface, though this has nothing to do with heatsinks cooling electronic components.
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10/27/2018, 09:49 AM | #22 | ||||
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Quote:
Quote:
Quote:
OR: Quote:
Like I said, w/ fans.. not an issue.. Last edited by oreo57; 10/27/2018 at 10:19 AM. |
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10/27/2018, 03:11 PM | #23 |
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Oreo57, let’s take a closer look at the info you posted.
Firstly, - “Matte-black surfaces will radiate much more efficiently than shiny bare metal.” Why? You then quoted, - “A shiny metal surface has low effective emissivity”. But areo57, you cut that quoted sentence short. The full sentence states, - “A shiny metal surface has low effective emissivity due to its low surface area.” Yes, a flat black surface is just that because it rough, it has greater surface area & absorbs more light. Whereas a shiny surface is shiny and reflects a lot of light because it’s smoother – less surface area. The greater the surface area the greater the radiative cooling (i.e. fins). Also think of it this way, -how shiny is that metal surface in pitch blackness? An object has no color in the dark. In the dark how could color possibly have any effect on its radiative ability? Surface area does affect radiative ability, in light or darkness. Your next quote states, - “Unless the component is facing a hotter surface nearby, it is imperative to have the heat sink surfaces painted or anodized to enhance radiation.” The author neither states why or how “painting” or “anodizing” enhances radiation, or the color the paint or anodizing should be. Black is not mentioned. Which brings us to your last quote. – “Heat sinks cooled by natural convection may benefit from an anodized finish” But, further along in the article it is stated, & I quote “The color of the anodized finish makes little impact on emissivity since most radiational heat loss occurs at wavelengths higher than visible light." . |
10/27/2018, 09:20 PM | #24 | ||
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Believe what you want to believe.. Black Anodizing increases passive cooling.
Just a known fact.. Yes other colors help too. If you can find ANY facts that state black anodizing "hurts" heat transfer under our conditions I'd be REALLY surprised.... Quote:
http://robots.freehostia.com/Heatsinks/Heatsinks.html https://www.ncbi.nlm.nih.gov/pmc/articles/PMC5455404/ Quote:
Last edited by oreo57; 10/27/2018 at 09:46 PM. |
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10/27/2018, 09:48 PM | #25 | ||
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Quote:
so again I'll ask; how could the actual color of a heatsink affect its ability to loose heat when operating in an environment of near dark, to, & especially, total darkness? It is light that gives an object its color; the color spectrum that an object cannot absorb, but reflects is the color it appears to the human eye. So in near, or total darkness a heatsink has no color. A black surface has a greater surface area than other colors & absorbs more light. Quote:
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